If sm n and sn m then sm+n
WebIf the sum of the first m terms of an AP be n and the sum of its first n terms be m then show that the sum of its first term is − (m + n). Q. If in an AP the sum of first m terms= n and the sum of first n terms= m, prove that sum of (m+n) term is -(m+n). Web21 okt. 2024 · closed Nov 25, 2024 by Ishti In an A.P. Sn denotes the sum to first n terms, if Sn = n2p and Sm = m2p (m ≠ n) prove that Sp = p3. arithmetic progression class-10 1 Answer +1 vote answered Oct 21, 2024 by Anika01 (57.3k points) selected Nov 25, 2024 by Ishti Best answer Given: Sn = n2p and Sm = m2p To Prove: Sp = p3 We know that,
If sm n and sn m then sm+n
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Web26 jul. 2024 · Given: S m = m 2 p and S n = n 2 p. To prove: S p = p 3. According to the problem (m - n)d = 2p(m - n) Now m is not equal to n So d = 2p. Substituting in 1 st … WebAnswer (1 of 2): Sn = n^2p Sm = m^2p Clearly, the above function can be written as Sx = x^2p So for p, the value of the function is Sp = p^2p = p*p*p = p^3
Web13 aug. 2011 · Sn= (a1+an)n/2 = (a1+a1+nd-d)n/2 =n (a1-d/2)+dn²/2 =an²+bn 其中,a= (a1-d/2),b=d/2 这么设是为了表示的方便而已。 所以有, Sn=an²+bn=m Sm=am²+bm=n 故Sm-Sn= (am²+bm)- (an²+bn)=a (m-n) (m+n)+b (m-n)=n-m 得知a (m+n)+b=-1 则Sm+n=a (n+m)²+b (n+m) = (n+m) [a (n+m)+b] =- (m+n) 以上~ 101 评论 gotoxyz 2024-06-04 · TA … Web21 okt. 2024 · If in an A.P., Sn = qn^2 and Sm = qm^2, where Sr denotes the sum of r terms of the A.P., then Sq equals asked Sep 7, 2024 in Arithmetic Progression by Chandan01 …
Web14 mei 2024 · Correct answer is C. P3 Let first term = a and Common difference = d ∴ According to the question, Sn = n2 p Sn = n/2 (2a + (n–1) d) = n2p 2a + (n–1) d = 2np………………. (1) And Sm = m2p Sm= m/2 (2a + (m–1) d) = m2p 2mp = (2a + (m–1) d)………………. (2) Subtracting 2 from 1 2a + (n–1) d – 2a – (m–1) d = 2np – 2mp d … Web26 mrt. 2024 · If Sn denotes the sum of first n terms of an A.P. a1 + a2 + a3 + ..., such that Sm/Sn = m^2/n^2 , then am/an = ? asked Nov 13, 2024 in Arithmetic Progression by Taanaya (23.8k points) sequences and series; class-10; 0 votes. 1 answer. If in an A.P., Sn = q n^2 and Sm = qm^2, where Sr denotes the sum of r terms of the A.P., then Sq ...
WebIf S n=n 2p and S m=m 2p,m =n, in an A.P, prove that S p=p 3 Medium Solution Verified by Toppr Given that ⇒S n=n 2p ⇒S n= 2n(2a+(n−1)d) ⇒ 2n(2a+(n−1)d)=n 2p …
Web26 jul. 2024 · Best answer Let the first term of the AP be a and the common difference be d Given: Sm = m2p and Sn = n2p To prove: Sp = p3 According to the problem (m - n)d = 2p (m - n) Now m is not equal to n So d = 2p Substituting in 1st equation we get Hence proved. ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test memorial wings vectorWeb17 mrt. 2024 · If Sm=n and Sn=m then Sm+n=? plz solve this See answer Advertisement Advertisement Cooloer Cooloer HOPE THIS WILL HELP..... Please mark as brainliest... but how I dont know answer is -(m+n) this answer is wrong Advertisement Advertisement New questions in Math. memorial wirelessWeb25 jul. 2024 · In an AP if Sm = n, Sn = m Prove that sum of (m+n) term is - (m + n) Class10 maths Izhar Sir . APT ADDA. 1.34K subscribers. Subscribe. 827 views 7 … memorial women\u0027s care pllcWebClick here👆to get an answer to your question ️ In an A.P. if SmSn = m^4n^4 then prove that Tm + 1Tn + 1 = (2m + 1)^3(2n + 1)^3 . Solve Study Textbooks Guides. Join / Login >> Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression memorial women\u0027s health atlantic blvdmemorial women\u0027s care 915 gessnerWebIf in an A.P., Sn = n 2 p and S m = m 2 p, where S r denotes the sum of r terms of the A.P., then S p is equal to Options 1 2 p 3 mn p P 3 (m + n) p 2 Advertisement Remove all ads Solution p 3 Given: S n = n 2 p ⇒ n 2 { 2 a + ( n − 1) d } = n 2 p ⇒ 2 a + ( n − 1) d = 2 n p ⇒ 2 a = 2 n p − ( n − 1) d..... ( 1) S m = m 2 p memorial women\u0027s healthcareWeb30 mrt. 2024 · We know that Sn = n/2 ( 2a + (n 1)d ) Where, Sn = sum of n terms of A.P. n = number of terms a = first term and d = common difference Thus, Sum of n terms = Sn = /2 (2a + (n 1)d) And Sum of m terms = Sm = /2 (2a + (m 1)d) It is given that, ratio of the sums of m and n terms of an A.P. is m2: n2 (Sum of m terms )/ (Sum of n terms) = m2/n2 (Sm … memorial women\\u0027s basketball